User input handling is very common and can normally use similar patterns. Basically, you re-ask for the input . You handle the valid choices and break out of the loop and you show an error when the choice is invalid and let the loop ask the input again. Remark1: by not using switch-case here, I can break out of the loop immediately.
The C language developers knew that, in some instances, a loop must be broken based on conditions that could not be predicted or set up inside the for statement. So, in their wisdom, they introduced the break keyword.. What break does is to immediately quit a loop (any C language loop , not just for loops ). When the computer sees break, it just assumes that the loop is done and continues as ...
but the problem is you receive an infinite loop . The reason behind this is when you hit returnenter on your keyboard, a newline character is passed in as input . These extra hidden characters are what is messing with your input and spawning the infinite while loop .
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Finally, although it's arguably a fairly minor point, this also tests the result of each input and output operation, and breaks out of the loop if either fails. If you don't do that, incorrect input can lead to an infinite loop , where the attempt to read fails, but leaves the data in the input stream, so the next iteration will fail again ...
In this tutorial, we will learn about for loop , and how to get user input in for loop in C++. What is a for iteration statement? A for iteration statement specifies counter-controlled-iteration details in a single line of code.A for loop is used when we know the number of times our loop has to run.The syntax of a for loop is as follows:
You could also interpret anything above 360 as 360, and anything below 0 as 0. Alternatively, interpret for example 500.7 as 140.7 degrees.
This code will loop until the user has entered an integer number. This way, the program doesn't simply report an error, but instead immediately allows the user to input again another, correct value.
In other words, the program enters an infinite loop ; if 42 was the last number that was successfully read, the program will print the message You entered 42 over and over. An easy way to check for invalid input is to move the input request from the body of the while loop into the control-expression of the while loop . E.g.,
C is a powerful language, but it will allow users to input garbage. It isn't the program's fault; after all, it is only doing what it is asked to do. If you as the programmer don't check for, or...